x(x+3)+5=x^2+7x-10

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Solution for x(x+3)+5=x^2+7x-10 equation: 



x(x+3)+5=x^2+7x-10

We move all terms to the left:

x(x+3)+5-(x^2+7x-10)=0

We multiply parentheses

x^2+3x-(x^2+7x-10)+5=0

We get rid of parentheses

x^2-x^2+3x-7x+10+5=0

We add all the numbers together, and all the variables

-4x+15=0

We move all terms containing x to the left, all other terms to the right

-4x=-15

x=-15/-4

x=3+3/4

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